Question

помогите пожалуйста решить ​

Answer 1

4 * 2 ⁻² = 2² * 2⁻² = 2²⁻² = 2⁰ = 1

$6*3^{-3}=6*\frac{1}{3^{3}}=\frac{6}{27}=\frac{2}{9}\\\\2*5^{-1}=2*\frac{1}{5}=\frac{2}{5}=0,4\\\\3*9^{-2}=3*(3^{2})^{-2}=3*3^{-4}=3^{1-4}=3^{-3}=\frac{1}{3^{3}}=\frac{1}{27}$

$a^{2}*a^{-3}=a^{2-3}=a^{-1}=\frac{1}{a}\\\\b^{4}*b^{-5}=b^{4-5}=b^{-1}=\frac{1}{b}\\\\d*d^{-2}=d^{1-2}=d^{-1}=\frac{1}{d}\\\\m^{5}*m^{-1}=m^{5-1}=m^{4}\\\\k^{6}:k^{-1}=k^{6-(-1)}=k^{6+1}=k^{7}\\\\L^{2}: L^{-1}=L^{2-(-1)}=L^{2+1}=L^{3}\\\\x^{3}:x^{-4}=x^{3-(-4)}=x^{3+4}=x^{7}\\\\y:y^{-3}=y^{1-(-3)}=y^{1+3}=y^{4}$