Question

$\frac{ {x }^ {2} - 6x + 5}{ \times - 1} \leqslant 0$
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Answer 1

$\frac{x^2-6x+5}{x-1}\leq 0\\\\\frac{(x-2)(x-3)}{x-1}\leq 0\\\\znaki:\; \; \; ---(1)+++[\, 2\, ]---[\, 3\, ]+++\\\\x\in (-\infty ,1)\cup [\, 2,3\, ]$