Question

Помогите, пожалуйста

Answer 1

Ответ:

$\frac{3d - c}{cd} - \frac{4c + 3d}{cd} = \frac{3d - c - 4c - 3d}{cd} = - \frac{5c}{cd} = - \frac{5}{d}$

$\frac{x + 2}{x - 2} + \frac{x}{x - 2} = \frac{x + 2 + x}{x - 2} = \frac{2x + 2}{x - 2} = \frac{2(x + 1)}{x - 2}$

$\frac{ {a}^{2} }{3a - 18} - \frac{36}{3a - 18} = \frac{ {a}^{2} - 36 }{3a - 18} = \frac{(a - 6)(a + 6)}{3(a - 6)} = \frac{a + 6}{3}$