Question

$\frac{8-5x}{3} -\frac{2-x}{2} =-\frac{x}{3}+\frac{4(x-2)}{5}$

Answer 1

$\frac{8-5x}{3}-\frac{2-x}{2}=-\frac{x}{3}+\frac{4(x-2)}{5}\\\\\frac{8-5x}{3}*30-\frac{2-x}{2}*30=-\frac{x}{3}*30+\frac{4x-8}{5}*30\\\\10(8-5x)-15(2-x)=-10x+24x-48\\\\80-50x-30+15x=14x-48\\\\-35x-14x=-48-50\\\\-49x=-98\\\\x=-98:(-49)\\\\x=2\\\\Otvet:\boxed{2}$