Question

срочно!!!
нелинейное уравнение!! ​

Answer 1

$\left \{ {{x-2y=2} \atop {xy=12}} \right.\; \; \left \{ {{x=2+2y} \atop {(2+2y)\cdot y=12}} \right.\; \; \left \{ {{x=2+2y} \atop {2y^2+2y-12=0}} \right.\; \; \left \{ {x=2+2y} \atop {y^2+y-6=0}} \right. \; \; \left \{ {{x_1=6\; ,\; x_2=-4} \atop {y_1=2\; ,\; y_2=-3}} \right. \\\\Otvet:\; \; (6,2)\; ,\; \; (-4,-3)\; .$