Question

Даю 35 баллов, пожалуйста срочно помогите

3 задания

Answer 1

Ответ:

$1) \frac{5}{2-x} + \frac{x-5}{x+2} + \frac{3x+8}{x^2-4} = 0\\\\5(-x-2) + (x-5)(x-2) + 3x+8 = 0\\\\-5x -10 + x^2 - 2x - 5x + 10 + 3x + 8 = 0\\\\x^2 -5x - 2x - 5x + 3x - 10 + 10 + 8 = 0\\\\x^2 - 9x + 8 = 0\\\\D = 81 - 32 = 49\\\\\sqrt{D} = 7\\\\x_1 = \frac{9-7}{2} = \frac{2}{2} = 1\\\\x_2 = \frac{9+7}{2} = \frac{16}{2} = 8\\\\  Otvet: \boxed{x_1 = 1; x_2 = 8}$

$2) x^2 - 2ax + a^2 = 0\\\\(x-a)^2 = 0\\\\x - a = 0\\\\x = a\\\\\frac{x}{a} = 1\\\\Otvet: \boxed{1}$

$3) \frac{3x}{5} = \frac{x^2+8}{10}\\\\x^2 + 8  = 2(3x)\\\\x^2 - 6x + 8 = 0\\\\D = 36 - 32 = 4\\\\\sqrt{D} = 2\\\\x_1 = \frac{6-2}{2} = \frac{4}{2} = 2\\\\x_2 = \frac{6+2}{2} = \frac{8}{2} = 4\\\\Otvet: \boxed{x_1 = 2; x_2 = 4}$