Question

Решите уравнение ((2y+3y/7)*14/17+(3y+2y/9)*27/29)*13=39

Answer 1

(17/7y*14/17+29/9y*27/29)*13=39

(y*2+y*3)*13=39

(2y+3y)*13=39

5y*13=39

65y=39

y=3/5

y=0,6

Удачи))

Answer 2

$((2y + \frac{3y}{7})*\frac{14}{17} + (3y+\frac{2y}{9})*\frac{27}{29})*13 = 39\\\\(2y + \frac{3y}{7})*\frac{14}{17} + (3y+\frac{2y}{9}*\frac{27}{29}) = 39 : 13\\\\(2y + \frac{3y}{7})*\frac{14}{17} + (3y+\frac{2y}{9})*\frac{27}{29}) = 3\\\\\frac{(2y+\frac{3y}{7})*14}{17} + \frac{(3y+\frac{2y}{9})*27}{29} = 3\\\\29(28y + 6y) + 17(81y + 6y) = 3*17*29\\\\812y + 174y + 1377y + 102y = 1479\\\\2465y = 1479\\\\y = 0,6$