Question

-3(1-y)+3(1-2y)=9 и 2((х-2)-2(х-1))+4х=1 пж срочно

Answer 1

Ответ:

$- 3$

И

$\frac{1}{2}$

Объяснение :

$- 3(1 - y) + 3(1 - 2y) = 9 \\ - 3 + 3y + 3 - 6y = 9 \\ - 3y = 9 \\ y = 9 \div( - 3 )\\ y = - 3$

$2((x - 2 )- 2(x - 1)) + 4x = 1 \\ 2(x - 2 - 2x + 2 ) + 4x = 1 \\ 2(- x ) + 4x = 1\\ - 2x + 4 x= 1 \\ 2x = 1 \\ x = \frac{1}{2}$