Question

3х+у/х^2+ху +х+3у/у^2+ху / дробная черта​

Answer 1

Ответ:

5ху+х+у

Объяснение:

$\frac{3x + y}{ {x}^{2} + xy } + \frac{x + 3y}{ {y}^{2} + xy} = \\ \frac{3x + y}{x(x + y)} + \frac{x + 3y}{y(y + x)} = \\ \frac{y(3x + y)+ x(x + 3y)}{xy(x + y)} = \\ \frac{3xy + {y}^{2} + {x}^{2} + 3xy }{xy(x + y)} = \\ \frac{6xy + {x}^{2} + {y}^{2} }{xy(x + y)} = \\ 5xy + x + y$