Question

решите уравнение х(х-4)=(х+3)
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Answer 1

Ответ:

$x(x-4)=(x+3)\\\\x^2 - 4x - x - 3 = 0\\\\x^2 - 5x - 3 = 0\\\\D = 25 + 12 = 37\\\\x_1 = \frac{5-\sqrt{37}}{2} = 2,5 - 0,5\sqrt{37}\\\\x_2 = \frac{5+\sqrt{37}}{2} = 2,5 + 0,5\sqrt{37}$