Question

Помогите пожалуйста!

Answer 1

Ответ:

Объяснение:

(8x⁻²/y⁻³)³·(2⁻⁴/(x⁻²y²))³=0,125y³

((2³y³/x²)³·(x²/(2⁴y²))³=(1/2)³y³

2³y³x⁻²x²·2⁻⁴y⁻²=2⁻¹y

2³⁻⁴y³⁻²x⁻²⁺²=2⁻¹y

2⁻¹y¹x⁰=2⁻¹y

2⁻¹y=2⁻¹y

y/2=y/2

y=y

(3³÷27)/(17⁰a⁻²) ·a³=a²/a⁻³

3³·3⁻³a²a³=a²a³

3³⁻³a²⁺³=a²⁺³

3⁰a⁵=a⁵

a⁵=a⁵

a=a

(5³÷75)/(19⁰b⁻²) ·b=5/(3b⁻³)

(5³÷(3·5²))b²b¹=5b³/3

5³·5⁻²/3 ·b²⁺¹=5b³/3

5³⁻²/3 ·b³=5b³/3

5b³/3=5b³/3

b³=b³

b=b