Question

1),2), и 3)
решите пожалуйста​

Answer 1

$1)5*8^{\frac{1}{3}}=5*(2^{3})^{\frac{1}{3}} =5*2=10\\\\Otvet:\boxed{10}\\\\2)16^{-\frac{1}{2}}=(\frac{1}{16})^{\frac{1}{2}}=[(\frac{1}{4})^{2}]^{\frac{1}{2}} =\frac{1}{4}=0,25\\\\Otvet:\boxed{0,25}$

$3)b^{\frac{1}{3}}*b^{-\frac{1}{6}}=b^{\frac{1}{3}-\frac{1}{6}}=b^{\frac{2}{6}-\frac{1}{6}}=b^{\frac{1}{6}}\\\\Otvet:\boxed{b^{\frac{1}{6}}}\\\\4)\frac{x^{\frac{3}{4}}*x^{\frac{1}{2}}}{x^{\frac{1}{4}}}=x^{\frac{3}{4}+\frac{1}{2}-1^{4}}=x^{\frac{3}{4}+\frac{2}{4}-\frac{1}{4}}=x\\\\Otvet:\boxed{x}$

$5)(y^{-\frac{3}{4}})^{4}*y^{\frac{5}{2}}=y^{-\frac{3}{4}*4}*y^{2,5}=y^{-3}*y^{2,5}=y^{-3+2,5}=y^{-0,5}\\\\Otvet:\boxed{y^{-0,5}}$

$6)a^{\frac{7}{2}}*\sqrt{a}=a^{\frac{7}{2}}*a^{\frac{1}{2}}=a^{\frac{7}{2}+\frac{1}{2}}=a^{4}\\\\Otvet:\boxed{a^{4}}$