Question

5x^2-12x+4/6-15x
Помогииитееее

Answer 1

Ответ:

(5х² -12х+4) / 6-15х = (5х² -10х -2х +4) /6-15х = ((5х² -10х) -(2х-4)) /3(2-5х)=            = (5х(х-2) - 2(х-2)) /3(2-5х) = (5х-2)(х-2) /- 3(5х-2) = -1/3(х-2)

Answer 2

$\frac{5x^{2}-12x+4}{6-15x}$

Разложим числитель на множители :

$5x^{2}-12x+4=0\\\\D=(-12)x^{2}-4*5*4=144-80=64=8^{2}\\\\x_{1}=\frac{12-8}{10} =\frac{4}{10}=0,4\\\\x_{2}=\frac{12+8}{10}=2\\\\5x^{2} -12x+4=5(x-0,4)(x-2)\\\\\frac{5x^{2}-12x+4 }{6-15x}=\frac{5(x-0,4)(x-2)}{3(2-5x)}=\frac{(5x-2)(x-2)}{3(2-5x)}=-\frac{x-2}{3}=\frac{2-x}{3}\\\\Otvet:\boxed{\frac{2-x}{3}}$