Question

ПОМОГИТЕ ПО-БРАТКИ❤️❤️❤️❤️
ДАМ 28 баллов!!!!!!

Answer 1

$\int \Big (\frac{1}{\sqrt[3]{x^2}}-\frac{1}{x\sqrt{x}}\Big )\, dx=\frac{x^{-2/3+1}}{-2/3+1}-\frac{x^{-3/2+1}}{-3/2+1}+C=\frac{x^{1/3}}{1/3}-\frac{x^{-1/2}}{-1/2}+C=\\\\=3\sqrt[3]{x}+\frac{2}{\sqrt{x}}+C\; ;\\\\\\\int (6x^5+7\, sinx)\, dx=6\cdot \frac{x^6}{6}+7\cdot (-cosx)+C=x^6-7\, cosx+C \; .$