Question

Решите уравнения
1.${20m}^{6} \times \frac{{3x}^{3} }{ {5m}^{9 } }$

2.$\frac{ {a}^{2} - 2ab }{ {a}^{2} + 3ab } \times \frac{ {a}^{2}b + {3ab}^{2} }{ {a}^{3} - {2a}^{2}b }$

3.$( - \frac{ {5a}^{3} {b}^{4} }{ {3c}^{5} {d}^{7} } {)}^{3}$
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Answer 1

Ответ:

Объяснение:

20m⁶·3x³/(5m⁹)=4m⁽⁶⁻⁹⁾·3x³=12m⁻³x³=12x³/m³

(a²-2ab)/(a²+3ab) ·(a²b+3ab²)/(a³-2a²b)=a(a-2b)/(a(a+3b)) ·ab(a+3b)/(a²(a-2b)=b/a

(-5a³b⁴/(3c⁵d⁷)³=-125a⁹b¹²/(27c¹⁵d²¹)