Question

Помогите, пожалуйста ​

Answer 1

$\frac{29+c^3}{c^{22}}-\frac{1}{c^{19}}=\frac{29+c^3}{c^{22}}-\frac{1*c^3}{c^{19}*c^3}=$

$=\frac{29+c^3}{c^{22}}-\frac{c^3}{c^{19+3}}=\frac{29+c^3}{c^{22}}-\frac{c^3}{c^{22}}=$

$=\frac{29+c^3-c^3}{c^{22}}=\frac{29}{c^{22}}$

Ответ: $\frac{29}{c^{22}}$