Question

..............помогите​

Answer 1

Объяснение:

$\tt\displaystyle \frac{6*3^{\frac{1}{3}}}{3^{\frac{2}{9}}*9^{\frac{1}{18}}}=\frac{2*3^{1}*3^{\frac{1}{3}}}{3^{\frac{2}{9}}*(3^{2})^{\frac{1}{18}} }=\frac{2*3^{1+^{\frac{1}{3}}}}{3^{\frac{2}{9}}*3^{\frac{1}{9}}}=\frac{2*3^{\frac{4}{3}} }{3^{\frac{2}{9}+\frac{1}{9}}}=\frac{2*3^{\frac{4}{3}}}{3^{\frac{1}{3}}}=2*3^{\frac{4}{3}-\frac{1}{3} }=2*3^{\frac{3}{3}}=2*3^{1}=2*3=6$

Answer 2

a^m*a^n = a^(m+n)

9 = 3^2

смотрим знаменатель

3^2/9 * 9^1/18 = 3^2/9 * 3^(2*1/18) = 3^(2/9 + 1/9) = 3^1/3

6*3^1/3 / 3^1/3 = 6