Question

помогите пожалуйста❤​

Answer 1

Ответ прикреплен во вложении

Answer 2

Объяснение:

2) $\frac{\sqrt{1-(\frac{4}{7})^{2} } }{{\frac{4}{7} } }=\frac{7\sqrt{1-(\frac{4}{7})^{2} } }{{4} } =\frac{7\sqrt{1-\frac{16}{49} } }{{4} }=\frac{7\sqrt{\frac{33}{49} } }{{4} }=\frac{7*\frac{\sqrt{33} }{7}  }{{4} }=\frac{\sqrt{33} }{4}$

3) $sin(arcsin(\frac{5}{12} ))cos(\frac{8}{17} ))+cos(\frac{5}{12} ))sin(arcsin(\frac{8}{17}))$

$\frac{5}{12} *\sqrt{1-(\frac{8}{17} )^{2} } +\sqrt{1-(\frac{5}{12})^{2} } *\frac{8}{17} =\frac{5}{12} *\sqrt{1-\frac{64}{289}}+\frac{8\sqrt{1-(\frac{5}{12})^{2} } }{17} =\frac{5}{12} *\sqrt{\frac{225}{289} } +\frac{8\sqrt{1-\frac{25}{144}} }{17} =\frac{5}{12} *\frac{15}{17} +\frac{8\sqrt{\frac{119}{144}} }{17} =\frac{5}{4}* \frac{5}{17} +\frac{8*\frac{\sqrt{119} }{12} }{17} =\frac{25}{68} +\frac{\frac{2\sqrt{119} }{3} }{17} =\frac{25}{68} +\frac{2\sqrt{119} }{51}$