Question

Задание прикреплено.

Answer 1

$Sin\alpha=-\frac{5}{\sqrt{26}}\\\\Cos\alpha=-\sqrt{1-Sin^{2}\alpha}=-\sqrt{1-(-\frac{5}{\sqrt{26}})^{2}}=-\sqrt{1-\frac{25}{26}}=-\sqrt{\frac{1}{26}} =-\frac{1}{\sqrt{26}}\\\\tg\alpha=\frac{Sin\alpha}{Cos\alpha}=-\frac{5}{\sqrt{26}}:(-\frac{1}{\sqrt{26}})=\frac{5*\sqrt{26}}{\sqrt{26}}=5\\\\Otvet:\boxed{tg\alpha=5}$