Question

Помогите сделать пожалуйста 4 упражнение
Буквы д, е, ж, з

Answer 1

Ответ:

$5) ((a)^2)^{\frac{1}{3}})^{\frac{3}{5}} = a^{\frac{2*3}{3*5}} = a^{\frac{2}{5}} = \sqrt[5]{a^2}\\\\6) \frac{3^{\frac{1}{3}}*7^{\frac{1}{3}}}{9^{\frac{1}{3}}} = \frac{3^{\frac{1}{3}}*7^{\frac{1}{3}}}{3^{\frac{1}{3}}*3^{\frac{1}{3}}} = \frac{7^{\frac{1}{3}}}{3^{\frac{1}{3}}} = \frac{\sqrt[3]{7}}{\sqrt[3]{3}}$

$7) (27^{\frac{2}{5}}*2^{\frac{1}{5}}*2)^{\frac{5}{6}} = (27^{\frac{2*5}{5*6}} * 2^{\frac{1*5}{5*6}}*2^\frac{5}{6}) = 27^\frac{1}{3} * 2^\frac{1}{6} * 2^\frac{5}{6} = 3*2^1 = 3*2 = 6\\\\8) (72^\frac{2}{3})^{\frac{1}{2}} * 36^\frac{1}{6} : 2^\frac{4}{3} = 72^\frac{1}{3} * 36^\frac{1}{6} : 2^\frac{4}{3} = 2^\frac{1}{3} * 36^\frac{1}{3} * 36^\frac{1}{6} : 2^\frac{4}{3} = 2^{\frac{1}{3}-\frac{4}{3}} * 36^{\frac{1}{3}+\frac{1}{6}} = \\\\ 2^{-1} * 36^{\frac{1}{2}} = \frac{1}{2}*6 = 3$

Answer 2

Д) (2*5)^2=100
Е)10^12-12= 1
Ж)2^8-6=4
З)100