Question

найти производную
1) y= 6 ³√x² - 7 tg³x
2) y=e^x arccos x

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Answer 1

1)

$y = \frac{4}{ \sqrt[3]{x} } - \frac{7 {tg}^{2} x}{ 3{cos}^{2} x}$

2)

$y = {e}^{x}* arccos x-{e}^{x}*\frac{1}{ \sqrt{1 - {x}^{2} } }$