Question

$\frac{a}{b} -\frac{a^{2} -b^{2} }{b^{2} } /\frac{a+b}{b}$

Answer 1

$\frac{a}{b} -\frac{a^{2} -b^{2} }{b^{2} } /\frac{a+b}{b} = \frac{a}{b} - \frac{(a - b)(a + b) \times b}{ {b}^{2}(a + b) } = \frac{a}{b} - \frac{a - b}{b} = \frac{a - (a - b)}{b} = \frac{a - a + b}{b} = \frac{b}{b} = 1$