Question

40 баллов!!!!хелп!!!! Срочно!!!!!​

Answer 1

Ответ: 12

Объяснение:

$25^{2-log_{5}75}=\frac{25^2}{(5^2)^{log_{5}75}} =\frac{25^2}{(5^{log_{5}75})^2} = \frac{25^2}{75^2} =(\frac{25}{75})^2=(\frac{1}{3} )^2=\frac{1}{9}$

$7^{-log_{7}3}=(7^{log_7{3}})^{-1}=3^{-1}=\frac{1}{3}$

$(\frac{1}{9} + \frac{1}{3} ) *27 = \frac{27}{9} + \frac{27}{3} = 3 + 9 = 12$

Answer 2

$(25^{2-log_{5}75}+7^{-log_{7} 3})*27=(25^{2}*25^{log_{5}\frac{1}{75}}+7^{log_{7}\frac{1}{3}}})*27=(625*(\frac{1}{75})^{2}+\frac{1}{3})*27=(\frac{25*25}{25*25*3*3}+\frac{1}{3})*27=(\frac{1}{9}+\frac{1}{3})*27=\frac{4}{9}*27=12\\\\Otvet:\boxed{12}$