Question

$32^{-2}*4^6$
реши

Answer 1

$32^{-2}cdot4^6=(2^5)^{-2}cdot (2^2)^6=2^{-10}cdot 2^{12}=2^{-10+12}=2^2=4$

Answer 2

$32^{-2}*4^6= (2^5)^{-2}*(2^2)^6=2^{-10}*2^{12}=2^{-10+12}=2^2=4$