Question

4x^2 + 48x + 76x + 912 = 1976
помогите,плс

Answer 1

$4x^2+48x+76x+912=1976<=>x^2+31x-266=0<=>\\<=>x^2+38x-7x-266=0<=>x(x+38)-7(x+38)=0<=>\\<=>(x+38)(x-7)=0\\x_1=-38\\x_2=7$

Answer 2

4x²+124x+912-1976=0

4x²+4*31x-1064=0

x²+31x-266=0

х₁,₂=(-31±√(31²+1064))/2=(-31±√(2025))/2=(-31±45)/2;

х₁=7; х₂=-38