Question

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А)2х/3у² • 4у/6х²
Б) (2х/х-1 + 3х/х-1) : 3/5х²

Answer 1

$\displaystyle\frac{2x}{3y^{2} } \times \frac{4y}{6x^{2} } =\frac{4}{3y\times3x} =\frac{4}{9xy} \\\bigg(\frac{2x}{x-1} +\frac{3x}{x-1} \bigg)\div\frac{3}{5x^{2} }=\frac{5x}{x-1} \times \frac{5x^2}{3} =\frac{25x^3}{3x-3}$