Question

4-x^2=3

10+x^2=6

1\2x^2=2

(x+2)^2=4

Answer 1

1. =  $x_{1}  = -1, x_{2} = 1$

2. = Нет решения ( X∉R)

3. = $x_{1}=-1, x_{2}=1$

4. = $x_{1}=-4, x_{2}=0$