Question

Решите уравнение: √12-х=6 ; √8х-1=1

Answer 1

1.

$\sqrt{12 - x} = 6$

ОДЗ: хє(-∞;12]

$12 - x = {6}^{2} \\ 12 - x = 36 \\ - x = 24 \\ x = - 24$

2.

$\sqrt{8x - 1} = 1$

ОДЗ: хє[1/8;+∞)

$8x - 1 = 1 \\ 8x = 2 \\ x = \frac{1}{4}$