Question

решить систему уравнений методом подстановки

2x^2-xy=33 и 4x-y=17

Answer 1

$left { {{y=4x-17} atop {[tex] 2x^{2}$-x(4x-17)=33}} right. [/tex]
$left { {{y=4x-17} atop {2 x^{2} -4 x^{2} +17x=33}} right.$
$left { {{y=4x-17} atop {-2 x^{2} +17x=33}} right.$
$left { {{y=4x-17} atop {-2 x^{2} +17x-33=0}} right.$
$-2 x^{2} +17x-33=0$
D=289-264=25
$x_{1} =3$
$x_{2} =5.5$
$y_{1} =4*3-17=-5$
$y_{2} =4*5.5-17=5$