Question

$left { {{ x^{2}+ xy-3y=9 } atop {{3x+2y=-1}} right.$

Answer 1

$x^2+xy-3y=9\ 3x+2y=-1\ \ x=frac{-1-2y}{3}\ frac{-1-2y}{3}^2+ frac{-1-2y}{3}*y-3y=9\ frac{4y^2+4y+1}{9}+frac{-y-2y^2}{3}-3y=9\ 4y^2+4y+1+3(-y-2y^2)-27y=81\ y=-8\ y=-5\ x=5\ x=3$