Question

Допоможіть будь ласка

Answer 1

$\frac{5}{x-3}-\frac{x-2}{x^{2}-9 }+\frac{x-1}{2x+6}=\frac{5}{x-3}-\frac{x-2}{(x-3)(x+3)}+\frac{x-1}{2(x+3)} =\frac{5*2*(x+3)-2*(x-2)+(x-1)*(x-3)}{2(x-3)(x+3)}=\frac{10x+30-2x+4+x^{2}-3x-x+3}{2(x-3)(x+3)}=\frac{x^{2}+4x+37}{2x^{2}-18 }$