Question

18 баллов, помогите пожалуйста

Answer 1

$x^{2}+2x\sqrt{2}+11=(\sqrt{2}+1)^{2}+2\sqrt{2}*(\sqrt{2}+1)+11=2+2\sqrt{2}+1+4+2\sqrt{2}+11=4\sqrt{2}+18\\\\Otvet:\boxed{18+4\sqrt{2}}$

Answer 2

($(\sqrt{2} +1)^2+2\sqrt{2} +1+11=2+2\sqrt{2} +1+2\sqrt{2} +1+11=15+4\sqrt{2}$