Question

1/2arccos(-1/2)+2arctg1+arctg√3 = ?

Answer 1

Ответ:

$\frac{7\pi}{6}$

Пошаговое объяснение:

$\frac{1}{2} *arccos(-\frac{1}{2} )+2*arctg1+arctg\sqrt{3} =\frac{1}{2} *\frac{2\pi }{3}+2*\frac{\pi}{4} +\frac{\pi}{3} =\frac{\pi }{3} +\frac{\pi}{2} +\frac{\pi}{3} =\frac{2\pi }{6}+\frac{3\pi}{6} +\frac{2\pi}{6} =\frac{7\pi}{6}$