Question

ctg3x+√3=0 корни уравнения

Answer 1

${\rm ctg}\, 3x+\sqrt{3}=0\\ \\ {\rm ctg}\, 3x=-\sqrt{3}\\ \\ 3x=\dfrac{5\pi}{6}+\pi n,n \in \mathbb{Z}\\ \\ \boxed{x=\dfrac{5\pi}{18}+\dfrac{\pi n}{3}, n\in \mathbb{Z}}$