Question

помогите не могу решить​

Answer 1

Ответ:

Объяснение:

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Answer 2

$y=\sqrt{x-4}+\frac{x-12}{x^2-16}\\\\\\OOF:\; \; \left \{ {{x-4\geq 0} \atop {x^2-16\ne 0}} \right.\; \; \left \{ {{x\geq 4\qquad \quad } \atop {(x-4)(x+4)\ne 0}} \right.\; \; \left \{ {{x\geq 4\qquad } \atop {x\ne -4\; ,\; x\ne 4}} \right.\; \; \Rightarrow \; \; \; x\in (4,+\infty )$