Question

log 7 (x + 3) = 49
log x 64 = 6

Answer 1

log₇(x+3) = 49

log₇(x+3) = log₇7⁴⁹

x + 3 = 7⁴⁹

x = 7⁴⁹ - 3

logₓ64 = 6

ОДЗ: $\displaystyle \left \{ {{x>0} \atop {x\ne 1}} \right.$

logₓ64 = logₓ x⁶

x⁶ = 64

x = ±2

Корень x = -2 не удовлетворяет ОДЗ, поэтому ответ x = 2.