Question

помогите пожалуйста (2x-1)^2=16​

Answer 1

Ответ:

$(2x - 1) {}^{2} = 16 \\ 2x - 1 = \frac{ + }{ - } 4 \\ 2x - 1 = 4 \\ 2x - 1 = - 4 \\ x1 = - \frac{3}{2} \\ x2 = \frac{5}{2} \\ x1 = - 1.5 \\ x2 = 2.5$

Answer 2

$(2x - 1)^{2} = 16 \\ 2x1 - 1 = 4 \\ 2x2 - 1 = - 4 \\ 2x1 = 5 \\ 2x2 = - 3 \\ x1 = \frac{5}{2} = 2.5 \\ x2 = \frac{ - 3}{2} = - 1.5$

Ответ: 2.5; -1.5