Question

La respuesta de la pregunta

Answer 1

Ответ:

${x}^{2} + {y}^{2} + 10x - 4y + 29 = 0 \\ {x}^{2} + 10x + 25 - 25 + {y}^{2} - 4y + 4 - 4 + 29 = 0 \\ ( {x}^{2} + 10x + 25) - 25 + ( {y}^{2} - 4y + 4) - 4 + 29 = 0 \\ {(x + 5)}^{2} + {(y - 2)}^{2} - 25 - 4 + 29 = 0 \\ {(x + 5)}^{2} + {(y - 2)}^{2} = 0$