Question

4Cos(x/2-pi/6)×dqrt12=0

Answer 1

4cos( \frac{x}{2}+ \frac{ \pi }{6})+ \sqrt{12}=0    

4cos( \frac{x}{2}+ \frac{ \pi }{6})=- \sqrt{12}   


cos( \frac{x}{2}+ \frac{ \pi }{6})=- \frac{ \sqrt{12} }{4}  

cos( \frac{x}{2} + \frac{ \pi }{6})=- \frac{ \sqrt{3} }{2}  

\frac{x}{2} + \frac{ \pi }{6} =+- \frac{5 \pi }{6}+2 \pi n,n

\frac{x}{2}  =+- \frac{5 \pi }{6}- \frac{ \pi }{6} +2 \pi n,n  

x=+- \frac{10 \pi }{6}- \frac{ 2\pi }{6} +4 \pi n,n

x =+- \frac{5 \pi }{3}- \frac{ \pi }{3} +4 \pi n,n