Question

Hайти сгоревшее вещество по дано

Answer 1

Ответ:

дано

m(CxHy) = 10.8 g

V(CO2)  = 17.92 L

m(H2O) = 10.8 g

p(CxHy) = 2.4 g/L

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CxHy-?

n(C) = n(CO2) = V / Vm = 17.92 / 22.4 = 0.8 mol

m(C) = n*M = 0.8 * 12 = 9.6 g

n(H) = 2n(H2O) = 2n(m/M ) = 2*10.8 / 18 = 1.2 g

m(H) = n*M = 1.2*1 = 1.2 g

m(O) = m(CxHy) - (m(C)+m(H)) = 10.8 -(9.6+1.2) = 0 g

n(C) : n(H) = 0.8:1.2 = 8 : 12 = 4 :6

C4H6

ответ C4H6

Объяснение: