Question

Решить:
$\sqrt{3 ^{6} \times {2}^{4} \times {7}^{2} }$
$\frac{0.7}{ \frac{5}{8} - \frac{3}{16} }$
​

Answer 1

Ответ:

756

1,6

Объяснение:

$\sqrt{3^6*2^4*7^2}=\sqrt{(3^3)^2*(2^2)^2*7^2}=3^3*2^2*7=27*4*7=756$

$\frac{0,7}{\frac{5}{8}-\frac{3}{16}}=\frac{\frac{7}{10}}{\frac{5*2-3}{16}}=\frac{\frac{7}{10}}{\frac{7}{16}}=\frac{7}{10}*\frac{16}{7}=1,6$

Answer 2

$1)\sqrt{3^{6}*2^{4} *7^{2}} =\sqrt{(3^{3})^{2}*(2^{2})^{2}*7^{2}}=3^{3}*2^{2}*7=27*4*7=756\\\\2)\frac{0,7}{\frac{5}{8}-\frac{3}{16}}=\frac{0,7}{\frac{10}{16}-\frac{3}{16}}=\frac{7}{10}:\frac{7}{16}=\frac{7}{10}*\frac{16}{7}=\frac{16}{10}=1,6$