Question

Помогите с 7 номером!!!!
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Answer 1

Ответ:

7.

$a) \sqrt{37 + 12} = \sqrt{49} = 7 \\ \sqrt{37 - 1} = \sqrt{36} = 6 \\ \sqrt{37 + 27} = \sqrt{64} = 8$

$\sqrt{37 - 28} = \sqrt{9} = 3 \\ \sqrt{37 + 63} = \sqrt{100} = 10$

Б)

$\sqrt{70 - 6} = \sqrt{64} = 8 \\ \sqrt{38 + 43} = \sqrt{81} = 9$

$\sqrt{ \frac{3}{4} + \frac{1}{18} } = \sqrt{ \frac{27}{36} + \frac{2}{36} } = \sqrt{ \frac{29}{36} } = \\ = \frac{ \sqrt{29} }{6}$