Question

Помогите, пожалуйста. Логарифмы $log_{\frac{1}{3} }8+log_{\frac{1}{3} }x=log_{\frac{1}{3} }4$

Answer 1

log(a) b + log(a) c = log(a) b*c

log(a) b = lod(a) c ⇒ b = c

log(1/3) 8 + log(1/3) x = log(1/3) 4

одз х > 0

log(1/3) 8*x = log(1/3) 4

8x = 4

x = 1/2