Question

Решите систему уравнений

Answer 1

x(2y-1)=3

y(2x-1)=5

x=3/(2y-1)

y(6/(2y-1) -1)= 5

x=3/(2y-1)

y((6-2y+1)/(2y-1))=5

x=3/(2y-1)

y((7-2y)/(2y-1))=5

x=3/(2y-1)

(7y-2y²-10y+5)/(2y-1)= 0

x=3/(2y-1)

(2y²+3y-5)/(2y-1)=0

D= 9+40=49

y1= (-3+7)/4= 1

y2= (-3-7)/4= -2,5

x1= 3

x2= -0,5

Ответ: (3;1), (-0,5; -2,5)