Question

Решите методом интервалов : $frac{3x+1}{x-2} geq 2$

Answer 1

$cfrac{3x+1}{x-2} geq 2 \ cfrac{3x+1-2(x-2)}{x-2} geq 0 \ cfrac{3x+1-2x+4}{x-2} geq 0 \ cfrac{x+5}{x-2} geq 0 \ xin(-infty;-5]cup(2;+infty)$