Question

Решите срочно срочно

Answer 1

Ответ:  $\displaystyle y=-\frac{1}{17} .$

Решение:

$\displaystyle \frac{3y+1}{2-y} = \frac{1-3y}{y+3} \\\\(3y+1)(y+3)=(2-y)(1-3y)\\3y^2+9y+y+3=2-6y-y+3y^2\\10y+3=2-7y\\17y=-1\\y=-\frac{1}{17} .$