Question

помогите решите весь пример
Дробные уравнения
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Answer 1

$\frac{x^{3}+3 }{x}=3x+1\\\\x^{3}+3=x(3x+1);x\neq 0\\\\x^{3}+3-3x^{2}-x=0\\\\(x^{3}-x)+(3-3x^{2})=0\\\\x(x^{2}-1)+3(1-x^{2})=0\\\\x(x^{2}-1)-3(x^{2}-1)=0\\\\(x^{2}-1)(x-3)=0\\\\(x-1)(x+1)(x-3)=0\\\\\\\left[\begin{array}{ccc}x-1=0\\x+1=0\\x-3=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1}=1 \\x_{2}=-1 \\x_{3}=3 \end{array}\right\\\\Otvet:-1;1;3$