Question

ПОМОГИТЕ 3x^2+13x-10=0​

Answer 1

${3x}^{2} + 13x - 10 = 0 \\ d = {13}^{2} - 4 \times 3 \times ( - 10) = 169 + 120 = 289 = {17}^{2} \\ x1 = \frac{ - 13 - 17}{3 \times 2} = \frac{ - 30}{6} = - 5 \\ x2 = \frac{ - 13 + 17}{6} = \frac{4}{6} = \frac{2}{3}$

Answer 2

D=169+120=289

x1= (-13+17)/6= 2/3

x2= (-13-17)/6= -5