Question

Комплексные числа.
найти: z1+z2; z1-z2; z1*z2; z1/z2
а)z1=7-2i
z2=-2+3i
б)z1=-2-4i
z2=5-3i
Очень надо решить.​

Answer 1

Ответ:

Пошаговое объяснение:

a) z1+z2=7-2i+(-2+3i)=7-2+3i-2i=5+i

    z1-z2=7-2i-(-2+3i)=7+2-2i-3i=9-5i

     z1*z2=(7-2i)(-2+3i)=-14+21i+4i-6$i^{2}[/tex=-14+25i+6=-8+25i</p><p>   z1/z2=[tex]\frac{7-2i}{-2+3i} =\frac{(7-2i)(2+3i)}{(-2+3i)(2+3i)} =\frac{14-4i+21i-6i^{2} }{-4+9i^{2} } =\frac{20+17i}{-4-9} =-\frac{20+17i}{13}$

б)  z1=-2-4i;  z2=5-3i

z1+z2=-2-4i+5-3i=3-7i

z1-z2=-2-4i-(5-3i)=-2-4i-5+3i=-7-i

z1*z2=(-2-4i)*(5-3i)=-10+6i-20i+12$i^{2}$=-22-14i

$\frac{z1}{z2} =\frac{-2-4i}{5-3i} =\frac{(-2-4i)(5+3i)}{(5-3i)(5+3i)} =\frac{-10-6i-20i-12i^{2} }{25-9i^{2} } =\frac{2-26i}{34}$