Question

sin(2x+п/4)+1=0 Решить Уравнение ​

Answer 1

$sin(2x+\frac{\pi}{4})+1=0\\\\sin(2x+\frac{\pi}{4})=-1\\\\2x+\frac{\pi}{4}=-\frac{\pi}{2}+2\pi n\; ,\; n\in Z\\\\2x=-\frac{3\pi}{4}+2\pi n\; ,\; n\in Z\\\\\boxed {x=-\frac{3\pi}{8}+\pi n\; ,\; n\in Z}$